How does f(x)=9^x change over the interval from x=8 to x=10

Step-by-step explanation:

9^8 to 9^10 involves a change (multiplication) of 9^8 by 9^2 (which is 81).

Over the given interval, f(x) increases by 81.

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0