Find the real zeros of the following function, and plot them on the graph. f(x)=(x^4-16)(x^2+3x-18)

Given function,

For zeros of function f(x),

f(x) = 0

By zero product property,

We get,

x = 2, -2, -2i, 2i, 3, -6

Hence, the real roots of f(x) are 2, -2, 3, -6.

Also, the roots lie at the point where a function intersects the x-axis.

Hence, the positions of the roots of f(x) in the graph are ,

(2, 0), (-2, 0), (3, 0) and (-6, 0)

2

step-by-2step explanation: