The lengths of trout in a lake are normally distributed with a mean of 30 inches and a standard deviation of 4.5 inches.

enter the z-score of a trout with a length of 28.2 inches.

-0.4

Step-by-step explanation:

z score is:

z = (x - μ) / σ

For x = 28.2, μ = 30, and σ = 4.5:

z = (28.2 - 30) / 4.5

z = -0.4

-0.4

Step-by-step explanation:

Given: Mean :

Standard deviation :

The formula to calculate z-score is given by :-

For X = 28.2 inches, we have

Hence, the z-score of a trout with a length of 28.2 inches.= -0.4

45.3592

step-by-step explanation: