What is the multiple zero and multiplicity of f(x)=x^3+2x^2+x? needed

a. multiple zero =-1; multiplicity = 2

b. multiple zero =1; multiplicity =2

c. multiple zero = 2; multiplicity =-1

d. multiple zero =2; multiplicity =1

f(x) = x³ + 2x² + x

f(x) = x.(x² + 2x + 1)

f(x) = x.(x + 1)²

So, f(x) = 0 when x = 0 or when x = -1

But

f(x) = x.(x + 1)² = x.(x + 1).(x + 1)

So we have three roots, x = 0, x = -1 and x = -1, although two of them are equal.

So we have a multiple zero x = -1 with a multiplicity 2.

Alterativa A.

option: d is correct

step-by-step explanation:

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%