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Mathematics, 08.10.2019 12:30 oomale

F(x) = 2x2 – 4x – 30 = 2x2 – 4x – 33 = 2(x2 – 2x)3 + 1 = 2(x2 – 2x + 1)4 = 2(x – 1)22 = (x – 1)2± = x – 11 ± = x mica is solving for the zeros of a quadratic function by completing the square. her work is shown. what error did mica make?

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F(x) = 2x2 – 4x – 30 = 2x2 – 4x – 33 = 2(x2 – 2x)3 + 1 = 2(x2 – 2x + 1)4 = 2(x – 1)22 = (x – 1)2± =...
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