Find the slope of a line perpendicular to 3x + 5y = 15.

a. -5/3
b. 5/3
c. -3/5
d. 3/5

B)5/3

Step-by-step explanation:

"3x + 5y = 15."

Rewrite in slope-intercept form.

The slope-intercept form is  

y=mx+b

where  m is the slope and  b  is the y-intercept.

y=mx+b

Subtract  3x  from both sides of the equation.

5y=15−3x

Divide each term by  "5"  and simplify.

5y/5=15/5−3x/5

"5" and "5" cancel each other out

Divide  15  by  5

y=3-3x/5

Reorder  3  and  −3x/5

y=-3x/5+3

Rewrite in slope-intercept form.

y=−3/5x+3

Slope:-3/5

The equation of a perpendicular line to  y=−3x/5+3  must have a slope that is the negative reciprocal of the original slope.

mperpendicular=−1/(−3/5)

Simplify the result.

mperpendicular=5/3

hope this helps!

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb