Identify the vertex of y = -1 (x-4)^2 +9 and tell whether it’s a minimum or maximum

and !

maximum at (4, 9)

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - 1(x - 4)² + 9 is in this form

with vertex = (4, 9)

• If a > 1 then vertex is a minimum

• If a < 0 then vertex is a maximum

here a = - 1 , hence vertex (4, 9) is a maximum

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*