Ineed urgent , i can't figure out this last question.
pr=35, pt= 10x-1 solve for x

9)

X=37/20

Explanation:

In a kite, one of the diagonals will bisect the other. So, 2(PT)=PR

By substitution, this becomes the equation

2(10x-1)=35

20x-2=35

20x=37

x=37/20

10)

Angle TQR is 52 degrees

Explanation:

A kite only bisects one set of opposite angles, so angle TQR is congruent to angle TQP. To find angle TQP use this equation:

Angle TPQ+Angle TQP=90

This is possible because angle QTP is right(diagonals of kites are perpendicular) and because all triangles have interior angles that add up to 180 degrees. The remaining amount of degrees apart from the right angle should be 90 degrees(180-90=90).

Substitute:

38+ angle TQP= 90

Angle TQP= 52 degrees

Angle TQP is congruent to angle TQR, so

Angle TQR=52 degrees

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