Suppose you invest $2,400 into a regular savings account with 3.95% annual interest rate that compounds quarterly. what would your investment be worth in 10 years? a. $2,400 b. $2,647.80 c. $3,555.63 d. $11,303

C, $3,555.63

Step-by-step explanation:

to answer this, we have to use the compound interest formula which is:

A = P(1 + r/n)^nt

the meanings of each variable are:

A = result

P = principal amount

r = rate (in decimal form)

n = the number of compound periods (eg: annually, quarterly, etc)

t = time

in the word problem, we need to solve for A. we are given P, r, n, and t.

P = 2,400

r = 0.0395 also known as 3.95%

n = 4 keyword being quarterly which is equal to the value of 4

t = 10

we can plug these values into the formula:

A = 2400(1 + 0.0395/4)^(4)(10)

we can use a calculator to calculate this easier but ill break it down:

A = 2400(1 + 0.0395/4)^(4)(10)

A = 2400(1 + 0.0395/4)^40

A = 800(1.009875)^40

A = 2400(1.48151088)

A ≈ 3555.626

we can round 3555.626 to the nearest hundredth which is $3555.63

you would have earned $3555.63 in 10 years

our answer would be C

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24