Aright triangle has side lengths ac = 7 inches, bc = 24 inches, and ab = 25 inches. what are the measures of the angles in triangle abc? m∠a ≈ 46.2°, m∠b ≈ 43.8°, m∠c ≈ 90° m∠a ≈ 73.0°, m∠b ≈ 17.0°, m∠c ≈ 90° m∠a ≈ 73.7°, m∠b ≈ 16.3°, m∠c ≈ 90° m∠a ≈ 74.4°, m∠b ≈ 15.6°, m∠c ≈ 90°

m∠C ≈ 90°m∠A ≈ 73.7°, m∠B ≈ 16.3°

Step-by-step explanation:

Given:

triangle ABC is right-angled triangle

let angle C= 90

using law of sines:

a/sinA=b/sinB

Putting the values:

25/sin90= 7/sinB

25/1=7/sinB

25sinB=7

sinB=7/25

sinB=0.28

B=sin^-1 (0.28)

B=16.3

As C= 90, B=16.3

A= 180-(90+16.3)

A=180-(106.3)

A=73.7 !

C) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

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