What is the largest of three consecutive positive integers if the product of the two smallest is equal to 2 more than 8 times the longest.

Step-by-step explanation:

n, n + 1, n + 2 - three consecutive integers

The equation:

n(n + 1) = 8(n + 2) + 2              ust the distributive property

n² + n = 8n + 16 + 2

n² + n = 8n + 18               subtract 8n from both sides

n² - 7n = 18          subtract 18 from both sides

n² - 7n - 18 = 0

n² - 9n + 2n - 18 = 0

n(n - 9) + 2(n - 9) = 0

(n - 9)(n + 2) = 0 ⇔ n - 9 = 0 or n + 2  =0

n - 9 = 0     add 9 to both sides

n = 9

n + 2 = 0          subtract 2 from both sides

n = -2 < 0

n + 2 = 9 + 2 = 11

answer:

step-by-step explanation:

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

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