Solve the equation p^2 + 2p - 8 = 0 using quadratic formula

p = 2        p = -4

Step-by-step explanation:

Find the solution for p^2+2p-8=0

using the Quadratic Formula where

a = 1, b = 2, c = -8

p = -b ±√(b^2 - 4ac)/2a

p = -2±√(2^2 - 4(1)(-8))/2(1)

p = -2±√(4 - (-32))/2

p = -2±√(36)/2

The discriminant b^2 - 4ac > 0

So, there are two roots.

Simplifying the radical

p = -2±6/2

p = -2+6/2 = 2

and

p = -2-6/2 = -4

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: