Cooper and drew are standing on the seashore 10 miles apart. the coastline is a straight line between them. both can see the same ship in the water. the angle between the coastline and cooper's view of the ship is 45 degrees. the angle between the coastline and drew's view of the ship is 35 degrees. how far is the ship from cooper?
a) 5.8 miles
b) 7.2 miles
c) 8.6 miles
d) 10 miles

Option A. 5.8 miles

Step-by-step explanation:

It is given in the question that angle SCD = 45°  and ∠ SAD = 35°

Distance between Cooper and Drew = 10 miles

Let distance between Ship and Cooper is = x miles

Now we apply Sine rule in the Δ SCD

By cross multiplication

(0.9848)x = 10(0.5736)

miles

Option A. 5.8 miles is the correct option.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

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step-by-step explanation: