Which equation yields the solutions x=−3 and x=−4?
a)2x2+14x+24=0
b)x2−6x+5=0
c)3x2+30x+48=0
d)−3x2−12x+15=0

a) 2x² + 14x + 24 = 0

Step-by-step explanation:

a)

2x² + 14x + 24 = 0

2(x + 4) (x + 3) = 0

x = -4 or x = -3

b)

x² - 6x + 5 = 0

(x - 1)(x - 5) = 0

x = 1 or x = 5

c)

3x² + 30x + 48 = 0

3 (x + 8) (x + 2) = 0

x = -8 or x = -2

d)

-3x² - 12x + 15 = 0

-3 (x + 5) (x - 1) = 0

x = -5 or x = 1

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine