For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?

Option C

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

If then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

.

Then the function k(x) that will have its vertex 7 units below f(x) is

42

step-by-step explanation:

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6