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Mathematics, 19.12.2019 04:31 darkremnant14

Find the sine, cosine, and tangent of 45 degrees.

a) sin 45 degrees = negative square root of 2 divided by 2, cos 45 degrees = negative square root of 2 divided by 2, tan 45 degrees = negative square root of 2

b) sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = square root of 2

c) sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = 1

d) sin 45 degrees = square root of 2 divided by 2, cos 45 degrees = square root of 2 divided by 2, tan 45 degrees = βˆ’1

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Find the sine, cosine, and tangent of 45 degrees.

a) sin 45 degrees = negative square ro...
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