Which pair of points is in the solution set for the system of linear inequalities below?
2x + y < 2
6x + 3y > 2
a.) (0, 3/2) and (3/4, 1/4)
b.) (1/2, 1) and (1/2,1/2)
c.) (-1,-1) and (0,-3)
d.) (0,2) and (1/3,0)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180