Aparking lot has the shape of a rectangle with two isoceles right trangles ( one one each end). what is the area of the parking lot if the rectangle 's dimensions are 45ft by 100ft? a) 5512.5 ft^2 b) 6525 ft^2 c) 8550 ft^2 d) 10012.5ft^2

Area of the parking lot = 6525 ft²

Explanation:

Since the two isosceles right-angled triangles have equal bases and heights, therefore, their areas are equal

Therefore:

Area of the parking lot = area of rectangle + 2*area of isosceles triangles

1- getting the area of the rectangle:

Area of rectangle = length * width

We are given that the dimensions of the rectangle are 45 ft and 100 ft

Therefore:

Area of rectangle = 45 * 100 = 4,500 ft²

2- getting the area of the isosceles triangle:

Area of triangle = 0.5 * base * height

From the drawing, we can note that:

base of triangle = height of triangle = smaller side of the rectangle = 45 ft

Therefore:

Area of triangle = 0.5 * 45 * 45 = 1,012.5 ft²

3- getting the total area:

Total area of parking lot = area of rectangle + 2*area of isosceles triangles

Total area of parking lot = 4500 + 2(1012.5)

Total area of parking lot = 6,525 ft²

Hope this helps :)

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5

more i think

hope this !