Acar purchased for $10,000 depreciates under a straight-line method in the amount of $750 each year. which equation below best models this depreciation? a. y = 1x + 750 b. y = 1 + 750x c. y = 1x - 750 d. y = 1 - 750x

D. y = 10000 - 750x

Step-by-step explanation:

The answer is D. y = 10000 - 750x, where:

y = the current value of the car,

10000 is the initial value of the car

750 is the depreciation it has every year

x is the number of years.

The 10000 has to be fixed and not multiplied by anything (unlike answer A or C) because that's the initial value of the car.  Then it has to be reduced (meaning we take value of out it, so a subtraction), so that excludes A and B.  The devaluation occurs every year, so it has to be multiplied by the number of years (excluding answers A and C again).  So, only answer D remains.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: