In exercises 18 and 19 determine which solution if any is an extraneous solution 18.sprt(3x-2)=x; x=1,x=2. 19. sprt(x+6=x; x=3,x=-2

ANSWER

18. No extraneous solution.

19. The extraneous solution is x=-2

EXPLANATION

18. The given radical equation is:

Solving this radical equation yields

We check for an extraneous solution by substituting each value into the equation.

Checking for x=1,

This is true.

Checking for x=2

This is also true. Hence there is no extraneous solution.

19. The given radical equation is:

Solving this equation yields,

Checking for x=3,.

3=3.

This is a true solution.

Checking for x=-2.

Hence x=-2 is an extraneous solution.

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)