The area of a rectangle is (x4 + 4x3 + 3x2 – 4x – 4), and the length of the rectangle is (x3 + 5x2 + 8x + 4). if area = length × width, what is the width of the rectangle?

Width = x-1

Step-by-step explanation:

Given

Area of rectangle=A= x^4+4x^3+3x^2-4x-4

Length of Rectangle=L= x^3+5x^2+8x+4

We have to find width

Width of rectangle=W= ?

We know that the formula for the area of triangle is:

Area of Rectangle=Length*Width

A=L*W

Since we need the value of width, length will be moved to the left of equals to.

A/L=W

W= (x^4+4x^3+3x^2-4x-4)/(x^3+5x^2+8x+4)

After long division, we will get

Width=W=x-1

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!