Given: m∠eyl=72° find: m ehl , m lve .

m(ARC)EHL: 108°

m(ARC)LVE: 252°

Step-by-step explanation:

Hey, so initially, we should start off with some stuff:

The sum of the arcs add up to 360°

m∠EYL=72°

We can create a system and use substitution to find the measure of an arc we don't know.

Step 1: We can use the 'Secants exterior angle theorem' to help us find the measure of (ARC)EHL.

<EYL=1/2((ARC)EVL-[ARC]EHL) (the theorem)

Step 2: By using substitution, we can say that (ARC)EVL=360°-(ARC)EHL

Thus, when we substitute it back into the theorem, the answer will be <EYL=1/2((360°-(ARC)EHL)-(ARC)EHL)=72°

Step 3: When we solve this out (and you can replace (ARC)EHL with x when solving), you will get an answer of x=108° or (ARC)EHL=108°.

Step 4: (ARC)LVE will be equal to 360°-m(ARC)EHL, which, when we substitute, will be 360°-108°, which will come out to be 252°.

Therefore, by algebra, substitution, and part-whole-postulate, (ARC) LVE=252°.

This is right, this was one of my problems for my 8th grade RSM online homework :)

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

cosine

step-by-step explanation: