The sum of two numbers is 12. the first number, x, is twice the second number, y, which system of equations could be used to find the two numbers ?

y=4, x=8

Step-by-step explanation:

system:

x+y = 12, x=2y

convert to 1 variable, simplify:

2y+y=12

3y=12

y=4

x=2y=4*2=8

The system of equations are:

x + y = 12

y = 2x  

Solution

x = 4

y = 12

Step-by-step explanation:

Given:

The sum of two numbers is 12. The first number, x, is twice the second number,y

Now we have to form the system of equations to find the solution.

The sum of two numbers is 12.

The first number = x

The second number y = 2x.

x + y = 12 (1)

y = 2x  --- (2)

These are the system of equations.

Now let's solve them.

Now plug in y = 2x in the first equation.

x + 2x = 12

Simplifying the like terms, we get

3x = 12

Dividing both sides by 3, we get

x = 4

To find the value of y, that is the second term, we need to plug in x = 4 in the second equation, we get

y = 2*4 = 8

So the first number is 4 and the second number is 8.

c. (3,2,6) is the answer.

0.32

step-by-step explanation:

2.24/7