Mathematics, 19.10.2019 21:00 sierram298

Aveterinarian investigating possible causes of enteroliths in horses suspects that feeding alfalfa may be to blame. she wishes to estimate the proportion of horses with enteroliths who are fed at least two flakes of alfalfa per day. in a sample of 62 horses with enteroliths, she finds 42 are fed two or more flakes of alfalfa. she estimates the standard error to be se = 0.0594. 0.2185. 0.0035. 0.4675.

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Answer from: lakaralake11

Step-by-step explanation:

Hello!

The veterinarian wants to test if eating alfalfa causes enteroliths in horses. For that, she takes a random sample of horses with enteroliths and counts how many eat alfalfa. The study variable is X: Number of horses with enteroliths that eat alfalfa in a sample of 62 horses.

Binomial criteria:

1. The number of observations of the trial is fixed.

2. Each observation in the trial is independent, this means that none of the trials will have an effect on the probability of the next trial.

3. The probability of success in the same from one trial to another.

Since the variable meets the binomial criteria, you can say that it has a binomial distribution, symbolically X ~ Bi (n;p)

To estimate the proportion of horses that have enteroliths and eat alfalfa you have to make the following calculation:

$p= \frac{x}{n} = \frac{42}{62} = 0.677$ ≈ 0.68

This means that 68% of the horses with enteroliths eat alfalfa.

To calculate the standard error you need to calculate the variance and then its square root:

V(X)= np(1-p)= 62*0.68*0.32 = 13.4912

$\sqrt{V(X)} = \sqrt{13.4912} = 3.6730$

None of the given options corresponds to the standard error of the sample.

I hope it helps!

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

Answer from: Quest

step-by-step explanation:

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