Write an equation with integer solutions of:

x = ±6, y = 0
and
x = 0, y = ±12

a)x2 + y2 + 6 = 0
b)4x2 + y2 + 144 = 0
c)x2 + y2 − 6 = 0
d)4x2 + y2 − 1

 Option 'D' is correct.

Step-by-step explanation:

Since we have given that

x = ±6, y = 0

and x = 0 and y = ±12

And we need an equation which has above as an integer solutions.

So, it becomes,

Consider

Put x = 0, we get

Similarly,

Put y = 0,

Hence, Option 'D' is correct.

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