Trig problem number 34.
10cosx+8sqrt2=8cos+7sqrt2

10 cos x +8sqrt2 = 8cos x +7 sqrt2   collect like times together to have

10cosx-8cosx = 8√2 - 7√2 then solve to have

2cosx = √2    divide by two in both sides

cosx=√2/2     but 2= √2 *√2

so cosx= √2/(√2 * √2)   so cos x =1/√2  but we know that cos inverse of 1/√2= 45   thus cos 45 = 1/√2 thus x = 45

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it