What is the equation of the line that passes through (-3,-1) and has a slope of 3/5

y+1 = 3/5(x+3)  (point slope form)

y = 3/5x +4/5 slope intercept form

Step-by-step explanation:

Since we have a point and a slope, we can use the point slope form of the equation

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y--1 = 3/5(x--3)

y+1 = 3/5(x+3)  (point slope form)

We can distribute

y+1 = 3/5x +9/5

Subtract 1 from each side

y+1-1 = 3/5x +9/5 -1

y = 3/5x +9/5 -5/5

y = 3/5x +4/5 slope intercept form

Equation:  y = 3/5 x + 4/5

Step-by-step explanation:

y = mx + b

so

b = y - mx

passes through (-3,-1) and has a slope of 3/5

So

b = -1 - (3/5) (-3)

b = -1 + 9/5

b = - 5/5 + 9/5

b = 4/5

So equation

y = 3/5 x + 4/5

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.