Passes through a(-3, 0) and b(-6, 5). what is the equation of the line that passes through the origin and is parallel to ?
a.
5x − 3y = 0
b.
-x + 3y = 0
c.
-5x − 3y = 0
d.
3x + 5y = 0
e.
-3x + 5y = 0

ANSWER

EXPLANATION

The line that passes through the origin has equation of the form:

y=mx

Where m is the slope.

Since the line is parallel to the line through A(-3, 0) and B(-6, 5), they have the same slope.

The slope is given by:

Hence the required equation is:

Multiply through by 3,

In standard form, the equation is

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation: