An airline has 82% of its flights depart on schedule. it has 65% of its flight depart and arrive on schedule. find the probability that a flight that departs on schedule also arrives on schedule. round the answer to two decimal places.

a. 0.80
b. 0.17
c. 0.53
d. 0.79

0.79

Step-by-step explanation:

Here,  

Let X be the event that the flights depart on time

Let Y be the event that flights arrive on time

So,  

X∩Y will denote the event that the flights departing on time also arrive on time.

Let P be the probability  

P(X∩Y)=0.65

And

P(X)=0.82

We have to find P((Y│X)

We know that

P((Y│X)=P(X∩Y)/P(X) )

=0.65/0.82

=0.79

So the probability that a flight that departs on schedule also arrives on schedule is: 0.79

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

5x+2x=49

7x=49

x=7. 35 apples