If sin theta equal 2/3 and theta is in quadrant 1, then what value of (tan theta)(cos theta)? !
a-2/3
b-3 square root 5/5
c-2 square root 5/3
d-square root 5/3

Option A. 2/3

Step-by-step explanation:

we know that

If angle theta is in Quadrant 1

then

The value of cos(theta) is positive and the value of tan(theta) is positive

Remember that

tan(theta)=sin(theta)/cos(theta)

In this problem we have

tan(theta)*cos(theta)=[sin(theta)/cos(theta)]*cos(theta)=sin(theta)

therefore

tan(theta)*cos(theta)=sin(theta)=2/3

the solution, from the graphing of the two lines, is (3,2), i.e., x = 3, y = 2.

the answer to this would be 5x^3-6x^2-24 over 3x^2

hope this if needed hmu