Anyone can you explain?

a goblet contains 3 red balls, 2 green balls, and 6 blue balls.

if we choose a ball, then another ball without putting the first one back in the goblet, what is the probability that the first ball will be red and the second will be blue?

9/55

P(1st = red and 2nd = blue)

= (3/11) x (6/10)

= 18/110

= 9/55

To find the probability of something happening,

= (number of desired outcomes) / (total number of outcomes)

If you are finding the probability of more than one thing happening at the same time, you multiply the probability of both things happening together

Idk idk idk idk idk idk idk idk