1. see 1st attached image down below. 2. see 2nd attached image down below. 3. see 3rd attached image down below. 4. see 4th attached image down below. 5. see 5th attached image down below.

1) The probability of rolling a 1 is 10/40 and the probability of rolling a 5 is 6/40. Add these together to get 16/40 which simplifies to 2/5 probability of rolling a 1 or 5.

2) The probability of the spinner landing on section 2 is 36/80 which simplifies to 9/20

3) To find the relative frequency, divide each number by the total number of trials. In this case we're only look at the clubs so divide 8/40, which is 0.2 or 20%

4) There were 60 trials total and since we're finding the relative frequency of red, divide 13/60 which is 0.216 rounded to 0.22 or 22%

5) The spinner is spun 84 times and it lands on A 14 times so the probability of it landing on A is 14/84 which simplifies to 1/6 or 0.166 rounded to 0.17 or 17%

I hope this helps you!

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!