Three classes at a junior high school raised money to buy new computers. ms. moore’s class raised $249.00. ms. aguilar raised $396.62 more than ms. moore’s class. mr. barry raised $430.43 less than ms. aguilar’s class. what is the total amount of money raised by all three classes?

The final amount is $1109.81

Step-by-step explanation:

In order to find the total amount, start with the know amount, which is Ms. Moore's class. Her class raised $249. Now we can use that to find the amount from Ms. Aguilar's class.

$249 + $396.62 = $645.62

Now we can use the amount from Ms. Aguilar's class to find the amount from Ms. Barry's class

$645.62 - $430.43 = $215.19

Now we can add the three amounts together to find the total amount.

$249 + $645.62 + $215.19 = $1109.81

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

f is the midpoint of