Abox contains 4 white balls and 6 yellow balls. a ball is drawn randomly from the box and is not replaced. what is the probability that both balls are white? a.) 3/25 b.) 8/45 c.) 2/15 d.) 4/25

C

Step-by-step explanation:

The question is actually, 2 balls are randomly taken and not replaced. What is the probability that both balls are white?

There are 4 while balls and 6 yellow balls. So total 10 balls.

The probability of a white ball at first draw is 4/10

** Since not replaced, so we have 1 less white ball and 1 less total ball. So there are now 3 white balls and 9 total balls.So:

The probability of a white ball at second draw is 3/9

We multiply both so: 4/10 * 3/9 = 2/15

Correct answer is C

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube