Avector has a magnitude of 50 in the 35º direction. what are the horizontal and vertical components of this vector?

Horizontal component: 40.95

Vertical component: 28.67

Step-by-step explanation:

To find the horizontal and the vertical component of this vector, you need:

The formula for calculate the horizontal component:

Where is the magnitude

The formula for calculate the vertical component:

Where is the magnitude

Given the angle 35 degrees and the magnitude,you can substitute values into the formulas.

Therefore, you get  that the horizontal component and the vertical component of this vector are:

Horizontal components = 40.95

Vertical components = 28.68

Step-by-step explanation:

We have to find the horizontal and vertical components of the vector given magnitude and direction of the vector.

To find the horizontal and vertical components the formula used is:

Vector u =( || u || cos θ , || u || sin θ )

where u = 50

and θ = 35

putting the values

Vector u =( 50 * cos (35) , 50 * sin (35))

              = (50 * 0.8191 , 50 * 0.5735)

             =(40.95,28.68)

so horizontal components = 40.95

vertical components = 28.68

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

step-by-step explanation:

where is the questions