Can someone me with this trigonometry problem. i would highly appreciate it if you did

x ≈ 16.52

Step-by-step explanation:

Use the tangent ratio in the right triangle to find x

tan36° = =

Multiply both sides by x

x × tan36° = 12 ( divide both sides by tan36° )

x = 12 / tan36° ≈ 16.52 ( to 2 dec. places )

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐