Write an equation in point-slope form and
slope-intercept form for the line that
passes through (-2,3) with a slope of 4.

y-3 = 4(x+2)  point slope form

y = 4x+11  slope intercept form

Step-by-step explanation:

Since we have a point and a slope, we will start with point slope form

y-y1 = m(x-x1)

y-3 = 4(x--2)

y-3 = 4(x+2)

This is point slope form

Distribute

y-3 = 4x+8

Add 3 to each side

y-3+3 = 4x+8+3

y = 4x+11

slope intercept form

Point slope form:y-3=4x+2

slope intercept form: 4x + 11 = y

Step-by-step explanation:

(-2,3)

-2=x1

3=y1

m=4

(y - y1) = m(x - x1)

-point slope form equation

(y - (3)) = 4(x - (-2))

- substitute values

y-3=4x+2-simplified equation

slope intercept:(to find intercept of slope you need to know where the slope begins)

find "b" first in y=mx+b:

and y1 as "y"

take(x1) as "x"- this is because (-2,3) is an x,y pair and we have an x and an y in "y=mx +b"

(3)=4(-2)+b

3=-8+b

add "8" to both sides

3+8=-8+8+b

11=b

since we know be we can solve for the y intercept in "y=mx+b"

y=4x+11-this is the "y" intercept

so slope intercept form= y=4x+11

hope this helps

step-by-step explanation: