One of the roots of the equation 3x2+7x−q=0 is −5. find the other root and q.
brainliest and 20 points

the other root is 8/3

q is 40

Step-by-step explanation:

Consider the product

(x -a)(x -b) = x^2 -(a+b)x +ab = 0

This is a quadratic with roots "a" and "b". We see that the x coefficient (-(a+b)) is the opposite of the sum of the roots, and that the final constant is their product. The leading coefficient in this quadratic is 1.

Dividing the given quadratic by 3, we see that the sum of the two roots is -7/3. So, the other root is ...

r = -7/3 -(-5) = 8/3

The product of the roots is -q/3, so ...

-q/3 = -5(8/3) = -40/3

q = 40 . . . . . . . . . . . . . multiply by -3

The other root is 8/3; the value of q is 40.