Abakery has a fixed cost of $119.75 per day plus $2.25 for each pastry. the bakery was like to keep its daily cost at or below $500 per day. which inequality shows the maximum number of pastries, p, that can be baked each day?

169 is the max number of pastries

Step-by-step explanation:

each pastry costs 2.25, so that will be the coefficient to p

inequality:

2.25p+119.75≤500

solve:

2.25p+119.75-199.75≤500-119.75(subtract 119.75 from both sides)

2.25≤300.25

divide by 2.25 on both sides

2.25p/2.25≤300.25/2.25

p≤169

hope this helps

he spend 5.1 minutes chatting with his friends.

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5.1

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: