Tony has a bucket filled with green, blue, yellow, and red markers. he removes 3 markers from the bucket, with replacement. select all outcomes that are possible.

Options A), B), C), D)

Step-by-step explanation:

There are 4 colors of markers.

Take out three "with replacement" markers.

As there is replacement, then the number of markers in the cube does not change in each trial.

A) There is a chance that when you get the three markers always get the same color.

B) It is likely to get a marker of each color

C) If 3 markers are taken it is likely to get the same amount of green and blue markers. For example, if there are 3 markers obtainable: blue, green, yellow. Then the number of blues and yellows is the same.

D) If 3 markers are taken it is likely to obtain the same amount of red and yellow markers. For example, if there are 3 markers you could obtain: red, yellow, blue. Then the number of reds and yellows is the same.

E) It is impossible for this to happen, because if only 3 markers of two different colors are taken, then there will always be 2 markers of one color and only one marker of another color:

green, green, yellow

blue, blue, green

blue, red, red

So the first 4 results are possible. Only the last result is impossible to obtain

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.