Solve this probability question:

an airplane has 50 seats, and each of its 50 passengers shows up with his/her ticket that has assigned seat. the first person to enter the plane forgets to look at his ticker and chooses a seat on random. each next person to enter the plane takes his assigned seat(if available or chooses a seat on random(if his/her seat his taken). what is the probability that the last passenger gets to sit in his assigned seat?

it is 1

Because there is 50 passengers and the is 50 seat

so 50÷50=1

so the probability will be 1

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.