How many triangles can be constructed with sides measuring 7cm,6cm, and 9cm?

a. none

b. more then one

c. one

C. One

OR

B. more than* one

Step-by-step explanation:

This answer actually depends on a couple of aspects, which the question is a bit unspecific about. It fails to clarify whether mirrored images/congruent triangles count as one or more than one. If there is any missing information, please quickly include it under the "Ask For Details."

HOW you solve this question is rather easy.

As you should know, there are dedicated theorems and equations for the majority of elements within Algebra, Calculus, Geometry, and sciences.

In this situation, you'd use the GEOMETRY triangle inequality theorem: IF the sum of any two sides is greater than or equal to the final side value, you've got a triangle.

Sides: 7cm, 6cm, 9cm.

7cm + 6cm  =  13cm; 13cm > 9cm

7cm + 9cm = 16cm; 16cm > 6cm

9cm + 6cm = 15cm; 15cm > 7cm

As you can see, you have all three possibilities with good prospects. Now, this is the complicated part. If Mirror Images/ Congruent Triangles are in the equation, all triangles will be congruent due to SSS (Side, Side, Side) configuration. This eliminates the possibilities for THREE total options and narrows it to ONE, because all triangles will be congruent.

The answer ultimately depends on the complete context of the question & the material you are currently covering.

If you've yet to learn of all the configurations and mirrored images, your answer is B: more than one

If you've ALREADY learned this and are currently utilizing the process, your answer is C. One

Personally, I'd lean more towards B., as most questions this simple don't take mirrored images or congruence into effect.

~Troy

idk

step-by-step explanation: