Acombination lock uses 4 numbers each of which can be 0-36 if there are no restrictions on the numbers how many possible combinations are there?
if i could get an explanation on this it with the answer it would be appreciated

0-36 equals 37 total numbers.

So each number in the combination could be one of 37 numbers.

1st number can be 1 of 37

2nd number is 1 of 37

3rd number is 1 of 37

4th number is 1 of 37

Multiply each possibility by each other.

Total number of combinations is 37 x 37 x 37 x 37 = 1,874,161

the distance from any point on the parabola to the focus is the exact same as the distance from that point to the directrix.

if you could provide answer choices that might allow me to answer the question easier if my above answer isn't an option! (:

i believe the correct answer is b.