Afield test for a new exam was given to randomly selected seniors. the exams were graded, and the sample mean and sample standard deviation were calculated. based on the results, the exam creator claims that on the same exam, nine times out of ten, seniors will have an average score within 5% of 75%. is the confidence interval at 90%, 95%, or 99%? what is the margin of error? calculate the confidence interval and explain what it means in terms of the situation.

the confidence interval is 90 % 0.05 < p < 0.75

and margin of error is 35 %

Step-by-step explanation:

Since 9 out of 10 students is 90 % so the confidence interval is 90 %

Range of Confidence Interval = 2* ME where ME = Margin of Error

0.75 - 0.05 = 2* ME

0.7 = 2 * ME

0.7 / 2 = ME

0.35 = ME or

ME = 35 %

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.