The graph shows the height (h), in feet, of a basketball t seconds after it is shot. projectile motion formula: h(t) = -16t2 + vt + h0 v = initial vertical velocity of the ball in feet per second h0 = initial height of the ball in feet complete the quadratic equation that models the situation. h(t) = –16t2 + t + 6 image description

h(t) = –16t^2 + 46*t + 6

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The projectile formula is

h(t) = -16*t^2 + v*t + h0

Where,

v = initial vertical velocity of the ball in feet per second

h0 = initial height of the ball in feet

We need to fill the equation

h(t) = –16t^2 + v*t + 6

Where

v is the missing speed

If we go through many values of v until we find the same graph as the one showed in the first picture, we can find that

v = 46 ft/s

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

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step-by-step explanation: