What is the equation in point slope form of the line passing through (0,6) and (1,3)

choices:
(y - 3) = -3(x - 1)
(y + 3) = 3(x + 1)
(y + 3) = -3(x + 1)
(y - 3) = 3(x + 6)

The equation will take the form (y-y)=m(x-x).  Since both coordinates are positive, the signs will be negative.  The answer is (y-3)=-3(x-1).

Hope this helps!!

sorry, can't i suggest going to algebra.com

step-by-step explanation:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: