Identify an equation in point-slope form for the line perpindicular to y=-1/2x+11 that passes through (4, -8)

a.) y+8=2(x-4)
b.) y-8=1/2(x+4)
c.) y+8=1/2(x+4)
d.) y-4=2(x+8)

y=4/2x+6

Step-by-step explanation:

I used Desmos to get my answer. I used a peice of paper to line up with the point and the original line.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

i think it is 18

step-by-step explanation: