Atotal of 28 tickets for the summer fair were sold. a child ticket costs $2.50 and an adult ticket costs $3.75. if the total cost of the tickets sold is $82.50, how many child tickets were sold?

18 tickets were sold

Step-by-step explanation:

The sum of the child tickets, C, and the adult tickets, A, is 28.  

Stated algebraically:

C+A=28

The cost per child’s ticket is $2.50 and the cost per adult’s ticket is $3.75, and the total cost was $82.50.  

Stated algebraically:

2.5C+3.75A=82.5

Multiply the first equation by −3.75 and use the method of elimination to directly solve for C:

−3.75C−3.75A=−105, which can be added to the second equation in order to eliminate the C variable:

2.5C+(−3.75C)+3.75A+(−3.75A)=82.5+(−105), which becomes:

−1.25C=−22.5, so C=18

b) well because you get well

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere