In the equation, t is a constant. if the equation has no real solutions, what could be the value of t? 2x^2 − 4x = t im struggling and my teacher doesnt teach me anything sooo

t>-2

Step-by-step explanation:

Given a quadratic equation ax²+bx+c = 0, the solutions to the equal can either be real or no real solution (complex).

For the equation to have a complex solution, the discriminant given as D = b²-4ac must be greater than zero i.e

b²-4ac > 0

Given the quadratic equation:

2x² − 4x = t

It can also be written as:

2x²-4x-t = 0

Where a = 2, b = -4 and c= -t

For the equation to have no real solution, b²-4ac > 0

(-4)² - 4(2)(-t) > 0

16+8t >. 0

16 > -8t

Dividing both sides by -8:

16/-8 < -8t/-8 (the sign change is because we divide both sides of the inequality by a negative value)

-2<t OR t>-2

The value of t will be greater than -2

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a