Given: measurement of arc ab=(5x+10)° , measurement of arc bc=(x+1)°,
measurement of arc cd=3x°, measurement of arc da=(3x+25)°.
find: m∠dpa

The measure of angle DPA is 39°

Step-by-step explanation:

step 1

Find the value of x

we know that

arc AB+arc BC+arc CD+arc DA=360°

substitute the values

(5x+10)°+(x+1)°+3x°+(3x+25)°=360°

Solve for x

(12x+36)°=360°

12x=360°-36°

x=324°/12=27°

step 2

Find the measure of angle DPA

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

m∠DPA=(1/2)[arc DA-arc BC]

arc DA=3(27)+25=106°

arc BC=27+1=28°

substitute the values

m∠DPA=(1/2)[106°-28°]=39°

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0